Originally Posted by **mikewhant** Hello, I wonder if anyone could check my answer to this problem.
Thanks in advance
An electron is liberated from the lower of two parallel plates separated by a distance of 5mm. The upper plate has a p.d. of 1000v relative to the lower plate. How long does it it take for the electron to reach to upper plate.
I said F=ma=QE therefore QE=ma
and since E=V/d=1000/0.005=2x105
a=QE/m
a=3.513x1016m/s2!
Then using s=ut+1/2at2, t=5.335x10-10s.
Thanks again for any help
Mike |

Hi there,

As long as your initial velocity, u, was zero, the mass you used was that of an electron, and lastly the charge , Q, was that of an electron, then your answer is correct. 1000V applied to such a tiny mass should cause it to undergo a great acceleration. Again this assumes that gravity has no effect on the electron, which is typically considered true. Then you should be able to set 0.005 = (1/2)at^2, plug in the value of, a, that you got, and then solve for the time, t.

Many Smiles,

Craig