Physics Help Forum Charged mass in electric field

 Electricity and Magnetism Electricity and Magnetism Physics Help Forum

 Sep 7th 2009, 03:39 PM #1 Junior Member   Join Date: Sep 2009 Posts: 2 Charged mass in electric field As shown in the figure above, a ball with a mass of 0.180 g and positive charge of q=36.0 μC is suspended on a string of negligible mass in a uniform electric field. We observe that the ball hangs at an angle of θ=18.0o from the vertical. What is the magnitude of the electric field? F=Mass*Gravity Convert to Coulombs first. Find the force of gravity on the object (Y direction),F=Mass*Gravity. Then determine the x component of using Force of gravity*TAN(Angle Given) Divide by Coulombs. based on those thoughts, I get .18*9.81 = 1.76580 next i take 1.77 * tan(18) = .57374 then i divided .57511/36E-6 = 15937.311 but its not the right answer =\
 Sep 7th 2009, 04:10 PM #2 Physics Team     Join Date: Jul 2009 Posts: 310 $\displaystyle F_g = mg$ $\displaystyle F_c = Eq$ $\displaystyle \tan \theta = \frac {F_c}{F_g}$ __________________ "Dissent is the highest form of patriotism." - Thomas Jefferson. "Give me control of a nation's money and I care not who makes her laws." -Mayer Amschel Rothschild I study Mathematical Physics at the University of Waterloo. -DC
 Sep 7th 2009, 05:52 PM #3 Junior Member   Join Date: Sep 2009 Posts: 2 umm that still gives me the same answer...assuming I am solving for E which is still wrong =\ i got 15937.326 however the numbers after the decimals dont really matter in this problem

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