Charge Problem
I had the problem:
An iron arrowhead has an initial charge of 3.35e−6 C. How many electrons are required to give it a charge of −2.82 μC?
This was my attempt
1) 2.82μC= 2.82e6 C
2) q=+/ Ne
3.35e6= N(1.6e19)
3) N= 3.35e6/1.6e19 = 2.09e13
4) 2.82e6= N(1.6e19)
5) N= 2.82e6/1.6e19= 1.76e13
6) 2.09e13 1.76e13 = 3.3e12 electrons.
The answer key says it should be 3.86e+13 electrons, so I'm close at least but I can't figure out what I did wrong, I checked my division and conversions several times. Any help would be great!
Thanks!!
