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Old Feb 22nd 2009, 02:45 AM   #1
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Ques.on magnitude(wit attachment)

Please refer the attachment for the diagram..pls advise me what to do,tq so much.

A wire of length 62.0 cm and mass 13.0 g is suspended by a pair of flexible leads in a magnetic field of 440 mT. Find the magnitude and direction of the current in the wire required to remove the tension in the supporting leads.
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Last edited by jonbrutal; Feb 22nd 2009 at 02:57 AM.
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Old Feb 28th 2009, 10:20 PM   #2
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My answer(correct???)

F = ma
= (0.013)(9.8)
=0.127N
F = ILB
0.127 = I(0.62)(440m)
I = 0.47A (direction is 90˚ downwards)
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