Originally Posted by **Tutan** We see in the Laplace equation (del^2)V=0 only if volume charge density is zero. But electric field intensity(E) is not equal to zero. What can be the physical situations to satisfy this equation.? |

Just like you said: (del^2)V = 0 if the volume contains no charge inside it. Electric field isn't a charge so it can exist within the volume.

Let's look at this in 1-D: (d^2V)/(dx^2) represents the curvature of V so the del^2 operator gives a version of a 3-D curvature.

-Dan