Physics Help Forum Internal Combustion Engine (Injectors)

 Feb 6th 2014, 02:59 AM #1 Junior Member   Join Date: Feb 2014 Posts: 3 Internal Combustion Engine (Injectors) I need a solution to this problem. An automobile has a 3.2-litter, five-cylinder, four-stroke cycle diesel engine [8] operating at 2400 RPM. Fuel injection occurs from 20° bTDC to 5° aTDC. The engine has a volumetric efficiency of 0.95 and operates with fuel equivalence ratio of 0.80. Light diesel fuel is' used. Calculate: Time for one injection, Fuel flow rate through an injector. If there are any assumptions made please let me know.
 Feb 7th 2014, 10:19 AM #2 Senior Member     Join Date: Apr 2008 Location: Bedford, England Posts: 668 The first part is relatively easy: 20° bTDC to 5° aTDC indicates fuel injection occurs over 25° of the cycle i.e 25/360 of one cycle of the cylinder 2400 rpm = 40 cycles per second = 0.025 seconds per cycle from this the time for one injection is readily determined. The second part requires an understanding of the terms: volumetric efficiency and fuel equivalence ratio which I don't have.
 Feb 7th 2014, 11:28 AM #3 Junior Member   Join Date: Feb 2014 Posts: 3 Thank You! I have figured them out right before 1 hour :P I thought it was more complicated than that! The second part: volumetric efficiency = ( mass of actual air) / (mass of ideal air) equivalence ratio = [(mass of fuel)/( mass of air)/ (mass of fuel)/( mass of air) in stoichiometric proportions]

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