 Nov 10th 2008, 11:29 AM #1 Junior Member   Join Date: Oct 2008 Posts: 12 Maxwell Boltzmann distribution. 1. The problem statement, all variables and given/known data The energy diﬀerence between the ﬁrst excited state of mercury and the ground state is 4.86 eV. (a) If a sample of mercury vaporized in a ﬂame contains 10^20 atoms in thermal equilibrium at 1600K, calculate the number of atoms in the n=1 (ground) and n=2 (ﬁrst-excited) states. (Assume the Maxwell-Boltzmann distribution applies and that the n=1 and n=2 states have equal statistical weights.) 2. Relevant equations Maxwell Boltzmann Distribution 3. The attempt at a solution I thought that since they have the same statistical weight, there must be 5*10^19 particles in each state. But I don't think it is the good answer since we use this number for another exercice and it doesn't yield the good answer. I don't know how to figure out these number using Maxwell Boltzmann distribution.  Tags boltzmann, distribution, maxwell Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Physics Forum Discussions Thread Thread Starter Forum Replies Last Post harve Electricity and Magnetism 12 May 4th 2017 01:05 AM imransaeed Electricity and Magnetism 2 Apr 30th 2015 03:44 PM MMM Advanced Optics 1 Apr 26th 2015 05:37 PM jabi Advanced Electricity and Magnetism 4 Aug 13th 2014 08:26 AM vyomictor Thermodynamics and Fluid Mechanics 0 Sep 3rd 2010 10:08 PM 