Quick calculation:
Required volume flow: 8 GPM = 1.07 ft^3/min = 18532 in^3/min = 30.9 in^3/s
For 1/2" pipe, with internal area of 0.2 in^2, required flow velocity = 30.9/0.2 = 157 in/s = 13.1 ft/s.
If the pump can deliver 80 psi for 8 GPM, the outlet velocity of the pump would be v = sqrt(2gh), where h = pressure in feet of head. 80 psi is equivalent to 185 feet of head (i.e., the pressure at the bottom of a tank that is 185 feet tall.) That's a lot of pressure! The expected outlet velocity is therefore sqrt(2 x 32.2 x 185) = 109 ft/s. In reality it would be a bit less due to losses, but this is a reasonable ball park calculation.
There will also be some loss of flow due to resistance of water along the inner wall of the 60 feet of pipe, but you have about a factor of 8 safety, so I see no problem in being able to deliver 8 GPM. In fact you would likely get close to 50 GPM, if the pump can maintain 80 psi at that flow rate.
