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 Advanced Optics Advanced Light and Optics Physics Help Forum Oct 20th 2009, 02:05 PM #1 Junior Member   Join Date: Feb 2009 Posts: 21 Equation for linearly polarized light I need to write an equation for a beam of polarized light traveling alone in the xy-plane 45 degrees from the x-axis. The plane of vibration corresponds to the xy-plane and the angular frequency is $\displaystyle \omega$ . Given the initial conditions: at t=0 the E-field at the origin is zero, normally, if the wave is propagating in the z-direction I would write: $\displaystyle \overrightarrow{E}=E_0\left [ \hat{i}sin(kz-\omega t)+\hat{j}sin(kz-\omega t) \right ]$ \overrightarrow{E}=E_0\left [ \hat{i}sin(kz-\omega t)+\hat{j}sin(kz-\omega t) \right ] But now the propagation direction has changed, how can I deal with that? Can I just change z to something else like: $\displaystyle \overrightarrow{E}=E_0\left [ \hat{i}sin(k?-\omega t)+\hat{j}sin(k?-\omega t) \right ]$ \overrightarrow{E}=E_0\left [ \hat{i}sin(k?-\omega t)+\hat{j}sin(k?-\omega t) \right ] Something is wrong with my latex, I've typed the codes below what I intended to display. Last edited by synclastica_86; Oct 20th 2009 at 02:08 PM.  Tags equation, light, linearly, polarized Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Physics Forum Discussions Thread Thread Starter Forum Replies Last Post kiwiheretic Light and Optics 8 Nov 19th 2018 01:58 AM kelsiu Advanced Waves and Sound 1 Jul 15th 2017 09:07 AM tizio Light and Optics 3 Apr 16th 2014 02:46 PM jaiii Quantum Physics 1 Feb 14th 2011 11:40 AM viciado Advanced Waves and Sound 0 Dec 16th 2009 08:03 AM