There are several formulas about the case of a pendulum.
One of them is that $\displaystyle T=2\pi \sqrt{\frac{l}{g}}$, where $\displaystyle T$ is the period of the pendulum, $\displaystyle l$ is the longitude of the pendulum and $\displaystyle g$ is the gravitational acceleration. In your sketch, we see that point A from point B is a quarter of a period. That is, the time taken for the pendulum to go from point A to point B is $\displaystyle \frac{T}{4}s$. Or, equivalently $\displaystyle \frac{\pi}{2}\cdot \sqrt{\frac{l}{g}}s$.
__________________ **Isaac** If the problem is too hard just let the Universe solve it. *
Last edited by arbolis; Oct 19th 2008 at 11:16 AM.
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