Physics Help Forum Another rotational motion problem.
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 Sep 4th 2008, 08:00 AM #1 Junior Member   Join Date: Sep 2008 Posts: 7 Another rotational motion problem. An overhead view of a ring that can rotate about its center like a merry go round. Its outer radius R is 0.8 m, its inner radius r is 0.4 m, its mass is 8 kg, and the mass of the crossbars in the ring is negligible. It initially rotates at an angular speed of 8rad/s with a cat of mass 2 kg on its outer edge, at radius R. By how much does the cat increase kinetic energy of the cat-ring system if the cat crawls to the inner edge, at radius r? (The answer is 39.1J --- From textbook) I don't know the solution. I tried to find initial and final moment of inertia (I) I-initial = (0.5)(8)((0.8^2)+(0.4^2)) + 2(0.8^2) = 4.48 kgm^2 I-final = (0.5)(8)((0.8^2)+(0.4^2)) + 2(0.4^2) = 3.52 kgm^2 Then I don't know how to do it. Please help. Thank you.
Sep 4th 2008, 08:28 AM   #2
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 Originally Posted by noppawit An overhead view of a ring that can rotate about its center like a merry go round. Its outer radius R is 0.8 m, its inner radius r is 0.4 m, its mass is 8 kg, and the mass of the crossbars in the ring is negligible. It initially rotates at an angular speed of 8rad/s with a cat of mass 2 kg on its outer edge, at radius R. By how much does the cat increase kinetic energy of the cat-ring system if the cat crawls to the inner edge, at radius r? (The answer is 39.1J --- From textbook) I don't know the solution. I tried to find initial and final moment of inertia (I) I-initial = (0.5)(8)((0.8^2)+(0.4^2)) + 2(0.8^2) = 4.48 kgm^2 I-final = (0.5)(8)((0.8^2)+(0.4^2)) + 2(0.4^2) = 3.52 kgm^2 Then I don't know how to do it. Please help. Thank you.
Rotational kinetic energy is
$\displaystyle K = \frac{1}{2}I \omega ^2$

-Dan
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