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Old Mar 31st 2009, 07:28 PM   #1
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Finding Net Torque

A bicyclist of mass 65.0 kg stands on the pedal of a bicycle. The crank, which is 0.170 m long makes a 45 degree angle with the vertical. The crank is attached to the chain wheel which has a radius of 9.70 cm . What force must the chain exert to keep the wheel from turning?


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Old Mar 31st 2009, 07:55 PM   #2
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The torque exerted by the weight of the man should be equal and opposite to that exerted by the force of the chain.
Torque = Force multiplied by the perpendicular distance of the line of action of force.

Torque exerted by the weight of the man = mg*0.17*sin45
Torque by the force by the chain = F*0.097 ( the chain is tangential to cranck, hence its perpendicular distance will be equall to the radius of the cranck.
For equilibrium
mg*0.17*sin45 = F*0.097, put the values, find F
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