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Old Dec 16th 2016, 05:58 AM   #1
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Maximum shear stress in mohr's circle

I am not sure how to get the maximum shear force in mohr's circle


To get the
$$\theta_(max) $$
θsmax , we have to 'turn' the B to
$$\tau_(max) $$
τmax , right ? So , it should be like this ( in the figure , orange arrow) ? Am i right ? Since at A , the shear stress is negative , we can only get the minimum shear stress by 'rotating ' the A to
$$\tau_(min) $$
τmin ? It 's not possible to get the maximum shear stress like the author do at point A , right ?

Last edited by ling233; Dec 16th 2016 at 06:05 AM.
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Old Dec 16th 2016, 06:00 AM   #2
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Old Dec 17th 2016, 03:30 AM   #3
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Old Dec 17th 2016, 03:31 AM   #4
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Old Dec 19th 2016, 07:29 AM   #5
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Old Jan 15th 2017, 10:44 AM   #6
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Maximum shear stress in mohr's circle

This example is correct.
Mohr circle takes a clockwise direction as positive and the positive direction of shear stress is downwards (Mechanical Engineering convention). All angles are taken from A which is at zero degrees. A check is that the principle stresses are perpendicular and that maximum shear stresses are 45 degrees from the principle stresses.
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