Originally Posted by **ChipB** Consider a small volume of fluid at the surface - it will have a force acting on it from pressure of fluid below that equals its acceleration. The angle of that normal force is dependent on the magnitudes of the horizontal acceleration a_x to the sum of vertical acceleration a_z plus g - it has slope (a_z+g)/a_x. Snce the normal force is perpendicular to the surface, the surface has slope -a_x/(a_z+g).
I assume you can take it from here. |

vertical rise of liquid
can you explain why the formula of vertical rise of liquid is like in the notes? why not Δs =

(g +az ) Δx / ax ? In the post above , you just explain about the ax and az , how to derive the formula ?