Physics Help Forum modified Faraday disc

 Oct 27th 2010, 05:53 AM #1 Junior Member   Join Date: Feb 2010 Posts: 1 modified Faraday disc the EMF for the Faraday disc is calculated as an integral of (v x B) between the disc axis and its edge. As for uniformly rotating disc v = w x r (B-field is orthogonal to the disc plane) one gets famous result: EMF = 1/2 w B R^2 , R - disc radius However such calculation works only if the integrand (v x B) is curl-free, then the integration does not depends on the contour and the EMF is well defined. But anybody can imagine that instead of solid disc we have a conducting fluid flowing out from the center and rotating. In this case v has radial component, curl(v x B) is non-zero and the integral for EMF depends on the shape of the contour. So then, what is the actual EMF ?
 Nov 24th 2010, 01:09 AM #2 Junior Member   Join Date: Nov 2010 Posts: 1 However such calculation works only if the integrand (v x B) is curl-free, then the integration does not depends on the contour and the EMF is well defined. But anybody can imagine that instead of solid disc we have a conducting fluid flowing out from the center and rotating......... __________________ Vlc Player Download

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