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Old Oct 27th 2010, 06:53 AM   #1
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modified Faraday disc

the EMF for the Faraday disc is calculated as an integral of (v x B) between the disc axis and its edge. As for uniformly rotating disc v = w x r (B-field is orthogonal to the disc plane) one gets famous result:
EMF = 1/2 w B R^2 , R - disc radius

However such calculation works only if the integrand (v x B) is curl-free, then the integration does not depends on the contour and the EMF is well defined. But anybody can imagine that instead of solid disc we have a conducting fluid flowing out from the center and rotating. In this case v has radial component, curl(v x B) is non-zero and the integral for EMF depends on the shape of the contour.
So then, what is the actual EMF ?
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Old Nov 24th 2010, 02:09 AM   #2
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However such calculation works only if the integrand (v x B) is curl-free, then the integration does not depends on the contour and the EMF is well defined. But anybody can imagine that instead of solid disc we have a conducting fluid flowing out from the center and rotating.........
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