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Old Mar 15th 2010, 02:25 PM   #1
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[SOLVED] velocity of rod in a magnetic field

A rod of mass m and radius R rests on two parallel rails (see diagram) that are a distance d apart and have a length L. The rod carries a current I in a direction perpendicular to the rails and rolls along the rails without slipping. A uniform magnetic field B is directed perpendicular to the rod and the rails. If it starts from rest, what is the speed of the rod as it leaves the rails?

i was thinking..
force due to interaction of field and current-carrying conductor:
F = iLxB = Bli

induced emf: e = BLv

so the velocity of rod: v = ei/F

am i in the right direction? any pointers?
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Last edited by greencheeseca; Mar 15th 2010 at 04:15 PM.
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