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Old Sep 12th 2018, 05:28 AM   #1
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Electric field, in the vertices of a triangle

in triangle ABC there are charges qa =-1.7X10-7C and qb =5.3X10-7. Find the intensity of the electric field in the vertex C
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Old Sep 12th 2018, 06:02 AM   #2
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You don't say which charge is where. Are we to assume that the first named charge, $\displaystyle 1.7\times 10^{-7}$ C, is at A and the second named charge, $\displaystyle 5.3 \times 10^{-7}$ C is at B?

If so this is pretty much just straight computation. The electric field at distance r from charge Q is give by $\displaystyle k_e\frac{Q}{r^2}$ where $\displaystyle k_e= 9\times 10^{9}$ $\displaystyle Nm^2/C^2$, "Coulomb's constant". Then add the field strength due to the two charges separately.
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