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 Advanced Electricity and Magnetism Advanced Electricity and Magnetism Physics Help Forum Apr 9th 2018, 08:02 AM #1 Senior Member   Join Date: Oct 2017 Location: Glasgow Posts: 443 Torque required for synchronising generators I had a query a while back on the physics part of MyMathForum. However, I never did manage to resolve it, so hopefully I'll have more success with you guys I'm trying to work out the answer to the following problem: Two, four-pole (p=2), 50 Hz synchronous generators are paralleled. Their phase displacement is 2 degrees mechanical. The synchronous reactance, $\displaystyle X$, of each machine is 10 Ohms/phase and the common busbar voltage is 6.6 kV. Calculate the synchronizing torque (answer = 968 Nm). The equation in the example problem for calculating this is: $\displaystyle \tau_{synch} = \frac{P_{synch}}{2\pi \frac{f}{p}}$ where $\displaystyle P_{synch} = \frac{3}{2} \frac{E^2}{X} \times \delta'_{el}$ I have no idea where this formula has come from. In the textbook the power of a turbo-generator is given as $\displaystyle P = \frac{EV}{X} \sin \delta$ where $\displaystyle V = E/\sqrt{3}$. However, this gives a different result. Does anyone know how the first formula is derived?  Tags generators, required, synchronising, torque Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Physics Forum Discussions Thread Thread Starter Forum Replies Last Post chasej562 Advanced Electricity and Magnetism 0 Jun 14th 2012 09:35 PM chasej562 Electricity and Magnetism 0 Jun 14th 2012 06:15 PM s3a Electricity and Magnetism 1 Apr 30th 2011 01:26 PM r.samanta Electricity and Magnetism 3 Nov 4th 2009 12:51 AM craka Advanced Mechanics 1 Sep 29th 2008 05:44 AM 